JEE MAIN 2024(29jan shift1)The resistance R=V/I where V=(200+_5)V and I=(20+_0.2)A, the percentage e

March 18, 2025

Written By Physics Monk

Vivek SIngh sir has 16+ years of experience in teaching physics, clearing doubts for IITJEE & NEET exams.

Description

*29th jan shift1 JEE MAIN Solutions****

****2024 complete solution playlist**😃🤘🏻

*****2025 complete solution playsit*****

***All JEE Main/AIEEE questions playlist***😃🤘🏻

***All NEET PYQs playlist***😃🤘🏻

✅✅✅😃You can also find for chapterwise playlist of JEE MAIN and NEET on the channel👍🏻👍🏻✅✅✅

#jee,#jeemain,#iitjee,#neet,#pyq,#importantquestions,#jeemainpapersolution,#jeemain2025,#physicsmonk

*29th jan shift1 JEE MAIN Solutions****

****2024 complete solution playlist**😃🤘🏻

*****2025 complete solution playsit*****

***All JEE Main/AIEEE questions playlist***😃🤘🏻

***All NEET PYQs playlist***😃🤘🏻

✅✅✅😃You can also find for chapterwise playlist of JEE MAIN and NEET on the channel👍🏻👍🏻✅✅✅

#jee,#jeemain,#iitjee,#neet,#pyq,#importantquestions,#jeemainpapersolution,#jeemain2025,#physicsmonk

The resistance R=V/I where V=(200+_5)V and I=(20+_0.2)A, the percentage error in the
measurement of R is :
(1) 3.5%
(2) 7%
(3) 3%
(4) 5.5%

#DoubthotoDoubtnutkaro

JEE MAIN 2024:(29jan shift1)The potential energy function (in J) of a particle ina region of space

JEE MAIN 2024(29jan shift1) A block of mass 100 kg slides over a distance of 10 m

Leave a Comment Cancel reply