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Vivek Singh
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Former Director β Vibrant Academy | Former Faculty β Aakash Institute
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JEE MAIN 2025(24jan shift1)The least count of a screw guage is 0.01 mm. If the pitch is increased b
February 19, 2025
Description The least count of a screw guage is 0.01 mm. If the pitch is increased by 75% and number of divisions on the circular scale is reduced by 50%, the new least count will be _____ Γ 10β3 mm. Welcome to Allen.AskDoubtnut.com β Indiaβs Largest Platform for Instant Doubt Solutions Allen.AskDoubtnut.com is the ultimate

JEE MAIN 2025(24 jan shift1)An alternating current is given by I = IA sinwt + IB coswtThe rms curren
February 19, 2025
Description An alternating current is given by I = IA sinwt + IB coswt The rms current will be Finding RMS of different types of AC With short method At 40:00 min Welcome to Allen.AskDoubtnut.com β Indiaβs Largest Platform for Instant Doubt Solutions Allen.AskDoubtnut.com is the ultimate destination for instant video solutions to your doubts
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