NEET2025:The electric field in a plane electromagnetic wave is given byEz = 60 cos (5x + 1.5 × 109

JEE MAIN 2024 Atom Structure: Rutherford Model Explanation | Watch Now!

JEE MAIN 2024 Atom Structure: Rutherford Model Explanation | Watch Now!

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JEE MAIN2024(29jan shift2)In the given circuit, the current in resistance R3 is :

JEE MAIN2024(29jan shift2)In the given circuit, the current in resistance R3 is :

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JEE MAIN 2024(29jan shift2)An electric field is given by E=(6i +5j +3k) N/C.The electric flux throug

JEE MAIN 2024(29jan shift2)An electric field is given by E=(6i +5j +3k) N/C.The electric flux throug

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JEE MAIN 2024(29jan shift1):the given circuit, the breakdown voltage of the Zener diode is 3.0 V. Wh

JEE MAIN 2024(29jan shift1):the given circuit, the breakdown voltage of the Zener diode is 3.0 V. Wh

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JEE MAIN 2024(29jan shift1)Given below are two statements:Statement I : If a capillary tube is immer

JEE MAIN 2024(29jan shift1)Given below are two statements:Statement I : If a capillary tube is immer

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JEE MAIN 2024(29jan shift1)Given below are two statements:Statement I : If a capillary tube is immer

JEE MAIN 2024(29jan shift1)Given below are two statements:Statement I : If a capillary tube is immer

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JEE MAIN 2024:(27jan shift2) Given below are two statements Assertion (A) : The angular speed of the

JEE MAIN 2024:(27jan shift2) Given below are two statements Assertion (A) : The angular speed of the

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