JEE MAIN 2024(27jan shift2)The atomic mass of 6C12 is 12.000000 u and that of6C13 is 13.003354 u. Th

March 17, 2025
Written By Physics Monk

Vivek SIngh sir has 16+ years of experience in teaching physics, clearing doubts for IITJEE & NEET exams.

JEE MAIN 2024(27jan shift2)The atomic mass of 6C12 is 12.000000 u and that of6C13 is 13.003354 u. Th

Description

*2024 (27th jan shift2) playslist*****πŸ‘πŸ»

JEE MAIN 2024: 27 jan shift 2 Solutions

****2024 complete solution playlist**πŸ˜ƒπŸ€˜πŸ»

JEE MAIN 2024 solutions(All shifts)

*****2025 complete solution playsit*****

JEE MAIN 2025 complete physics solutions(paper discussion)

***All JEE Main/AIEEE questions playlist***πŸ˜ƒπŸ€˜πŸ»

All JEE MAIN /AIEEE ExamPYQs

***All NEET PYQs playlist***πŸ˜ƒπŸ€˜πŸ»

All NEET/AIIMS/AIPMT PYQs

βœ…βœ…βœ…πŸ˜ƒYou can also find for chapterwise playlist of JEE MAIN and NEET on the channelπŸ‘πŸ»πŸ‘πŸ»βœ…βœ…βœ…

#jee,#jeemain,#iitjee,#neet,#pyq,#importantquestions,#jeemainpapersolution,#jeemain2025,#physicsmonk

The atomic mass of 6C12 is 12.000000 u and that of
6C13 is 13.003354 u. The required energy to
remove a neutron from 6C13, if mass of neutron is
1.008665 u, will be :
(1) 62. 5 MeV (2) 6.25 MeV
(3) 4.95 MeV (4) 49.5 MeV

#DoubthotoDoubtnutkaro

Leave a Comment

Exit mobile version