Description
*2024(29th jan shift 2) solutions***๐
****2024 complete solution playlist**๐๐ค๐ป
*****2025 complete solution playsit*****
***All JEE Main/AIEEE questions playlist***๐๐ค๐ป
***All NEET PYQs playlist***๐๐ค๐ป
โ โ โ ๐You can also find for chapterwise playlist of JEE MAIN and NEET on the channel๐๐ป๐๐ปโ โ โ
#jee,#jeemain,#iitjee,#neet,#pyq,#importantquestions,#jeemainpapersolution,#jeemain2025,#physicsmonk
A wire of length L and radius r is clamped at one end. If its other end is pulled by a force F, its length increases by l. If the radius of the wire and the applied force both are reduced to half of their original values keeping original length constant, the increase in length will become.
(1) 3 times 2) 3/2 times. 3)4 times 4) 2 times
Welcome to Allen.AskDoubtnut.com โ Indiaโs Largest Platform for Instant Doubt Solutions
Allen.AskDoubtnut.com is the ultimate destination for instant video solutions to your doubts in Physicsโfrom Class 11th to JEE Advanced and NEET level. With a growing library of over 15 lakh+ expert-created video solutions, we make learning fast, easy, and effective.
Just click a photo of your doubt using the AskDoubtnut in the end and submit in google, and get an instant, step-by-step video explanation. Itโs the simplest way to solve doubts in secondsโwhether youโre studying for CBSE board exams, IIT-JEE, NEET, or any other competitive exam.
Why AskDoubtnut.com?
โข 10,00,000+ Free Video Solutions
โข Covers NCERT, JEE Main, JEE Advanced, NEET, and State Boards
โข Unlimited Doubt Solving with Just One Click
โข Instant, Concept-Based Answers by Experts
โข 24×7 Learning Support via the AskDoubtnut App
Trusted by millions of students across India, Allen.AskDoubtnut.com helps you turn doubts into confidence. No more waitingโask, learn, and grow with Allen.AskDoubtnut.com!
- Master JEE Physics: Understanding Unpolarised Light Intensity with Polaroid Filters
- JEE MAIN 2024(29th jan shift 2) Power of Light Intensity Derivation | JEE/NEET Solutions
- JEE MAIN 2024(29jan shift2)A planet takes 200 days to complete one revolution around the Sun. If the
- JEE MAIN 2024(29jan shift2)N moles of a polyatomic gas (f = 6) must be mixed with two moles of a mo
- JEE MAIN 2024(29jan shift2)Given below are two statements :Statement I : Most of the mass of the ato
- Master JEE Physics: Solve Unpolarised Light Intensity with Polaroid Filters
- JEE MAIN 2024 Power of Light Intensity Derivation | JEE/NEET Solutions
- JEE MAIN 2024(29th Jan Shift 2) Solutions: Planet Revolution Time Reduction
- JEE MAIN 2024(29jan shift2)N moles of a polyatomic gas (f = 6) must be mixed with two moles of a mo
- JEE MAIN 2024(29jan shift2)Given below are two statements :Statement I : Most of the mass of the ato
- Master JEE Physics: How to Solve Unpolarised Light Intensity with Polaroid Filters
- JEE MAIN 2024 Power of Light Intensity Derivation | JEE/NEET Solutions | Watch Now!
- JEE MAIN 2024(29th Jan Shift 2) Solutions: Revolution Time Reduction | Watch Now!
- JEE MAIN 2024(29th Jan Shift 2) Gas Mixture Problem Solution | NEET/JEE Doubt
- JEE MAIN 2024(29th Jan Shift 2) Atom Structure: Rutherford Model Explanation
- Master JEE Physics: How to Solve Unpolarised Light Intensity with Polaroid Filters | JEE/NEET Solutions
- JEE MAIN 2024 Power of Light Intensity Derivation | Watch Now! | JEE/NEET Solutions
- JEE MAIN 2024(29th Jan Shift 2) Solutions: Revolution Time Reduction | Watch Now!
- JEE MAIN 2024(29th Jan Shift 2) Gas Mixture Problem Solution | NEET/JEE Doubt – Find Nmoles of Gas
- JEE MAIN 2024 Atom Structure: Rutherford Model Explanation | Watch Now!
- NEET 2025:To an ac power supply of 220 V at 50 Hz, a resistor of 20 ฮฉ, a capacitor of reactance 25
- NEET 2025: (By 2 methods)In some appropriate units, time (t) and position (x) relation of a moving p
- NEET 2025: AB is a part of an electrical circuit (see figure). The potential difference โVA โ VBโ, a
- NEET 2025:A ball of mass 0.5 kg is dropped from a height of 40 m. The ball hits the ground and rises
- NEET 2025:A bob of heavy mass m is suspended by a light string of length l. The bob is given a horiz
Frequently Asked Questions
How to prepare for IIT-JEE Physics?
To prepare for IIT-JEE Physics, focus on understanding concepts rather than memorizing formulas. Practice solving a variety of problems, especially previous years’ questions. Create a study schedule that covers all topics, with extra time for challenging areas like Mechanics and Electromagnetism. Regular revision and mock tests are essential for success.
How do you solve projectile motion problems?
To solve projectile motion problems, break the motion into horizontal and vertical components. The horizontal motion has constant velocity (ax = 0), while the vertical motion has constant acceleration due to gravity (ay = g). Use the equations of motion separately for each component, and remember that the time is the same for both components.
What is the difference between electric potential and electric potential energy?
Electric potential is the electric potential energy per unit charge, measured in volts (V). It’s a property of a point in space. Electric potential energy is the energy possessed by a charge due to its position in an electric field, measured in joules (J). It depends on both the charge and its position.