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An amount of ice of mass 10–3 kg and temperature –10°C is transformed to vapour of temperature 110° by applying heat. The total amount of work required for this conversion is,
(Take, specific heat of ice = 2100 Jkg–1K–1, specific heat of water = 4180 Jkg–1K–1, specific heat of steam = 1920 Jkg–1K–1, Latent heat of
ice = 3.35 × 105 Jkg–1 and Latent heat of steam = 2.25 × 106 Jkg–1
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