JEE MAIN 2024(27jan shift2): By 2 methods of calculation A closed organ pipe 150 cm long gives 7 bea

March 13, 2025

Physics Monk

JEE MAIN 2024(27jan shift2): By 2 methods of calculation A closed organ pipe 150 cm long gives 7 bea

Description

*2024 (27th jan shift2) playslist*****πŸ‘πŸ»

JEE MAIN 2024: 27 jan shift 2 Solutions

****2024 complete solution playlist**πŸ˜ƒπŸ€˜πŸ»

JEE MAIN 2024 solutions(All shifts)

*****2025 complete solution playsit*****

JEE MAIN 2025 complete physics solutions(paper discussion)

***All JEE Main/AIEEE questions playlist***πŸ˜ƒπŸ€˜πŸ»

All JEE MAIN /AIEEE ExamPYQs

***All NEET PYQs playlist***πŸ˜ƒπŸ€˜πŸ»

All NEET/AIIMS/AIPMT PYQs

βœ…βœ…βœ…πŸ˜ƒYou can also find for chapterwise playlist of JEE MAIN and NEET on the channelπŸ‘πŸ»πŸ‘πŸ»βœ…βœ…βœ…

#jee,#jeemain,#iitjee,#neet,#pyq,#importantquestions,#jeemainpapersolution,#jeemain2025,#physicsmonk

A closed organ pipe 150 cm long gives 7 beats per second with an open organ pipe of length 350 cm, both vibrating in fundamental mode. The velocity
of sound is ________ m/s.

#DoubthotoDoubtnutkaro

About the author

With over 15 years of teaching experience, Vivek Singh Sir has served as Head of Department and Academic Head at premier institutions such as Aakash Institute, Narayana, Career Point, and has also worked as the Director of Vibrant Academy Bilaspur.

Leave a Comment

Exit mobile version