JEE MAIN 2024(29jan shift1)The resistance R=V/I where V=(200+_5)V and I=(20+_0.2)A, the percentage e

March 18, 2025
Written By Physics Monk

Vivek SIngh sir has 16+ years of experience in teaching physics, clearing doubts for IITJEE & NEET exams.

JEE MAIN 2024(29jan shift1)The resistance R=V/I where V=(200+_5)V and I=(20+_0.2)A, the percentage e

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*29th jan shift1 JEE MAIN Solutions****
JEE MAIN 2024:(29th jan shift1) Solutions

****2024 complete solution playlist**πŸ˜ƒπŸ€˜πŸ»

JEE MAIN 2024 solutions(All shifts)

*****2025 complete solution playsit*****

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***All JEE Main/AIEEE questions playlist***πŸ˜ƒπŸ€˜πŸ»

All JEE MAIN /AIEEE ExamPYQs

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The resistance R=V/I where V=(200+_5)V and I=(20+_0.2)A, the percentage error in the
measurement of R is :
(1) 3.5%
(2) 7%
(3) 3%
(4) 5.5%

#DoubthotoDoubtnutkaro

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