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JEE MAIN 2024(29jan shift1)Given below are two statements:Statement I : If a capillary tube is immer
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JEE MAIN2024(29jan shift2)In the given circuit, the current in resistance R3 is :
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JEE MAIN 2024(29jan shift1)The resistance R=V/I where V=(200+_5)V and I=(20+_0.2)A, the percentage e
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JEE MAIN 2024(29jan shift1)Match List I with List IIGauss’law forelectricityGauss’law formagnetism
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JEE MAIN 2024(29th Jan Shift 2) Solutions: Revolution Time Reduction | Watch Now!
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JEE MAIN 2024(29jan shift1):the given circuit, the breakdown voltage of the Zener diode is 3.0 V. Wh
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Two charges of 5Q and –2Q are situated at the
points (3a, 0) and (–5a, 0) respectively. The
electric flux through a sphere of radius ‘4a’ having
center at origin is :
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